The T1 matrix of the device under test is found as:
\begin{equation} T_{1}=\left[\begin{matrix}A & B\\0 & 0\end{matrix}\right] \end{equation}The matrix equation for the two-port (DUT) is found as:
\begin{equation} \left[\begin{matrix}V_{i}\\I_{i}\end{matrix}\right]=\left[\begin{matrix}A V_{o} + B I_{o}\\0\end{matrix}\right] \end{equation}The source-to-load transfer is obtained as:
\begin{equation} A_{v}=\frac{R_{\ell}}{A R_{\ell} + B} \end{equation}The input impedance is found as:
\begin{equation} z_{i}=\tilde{\infty} \left(A R_{\ell} + B\right) \end{equation}The output impedance is found as:
\begin{equation} z_{o}=\frac{B}{A} \end{equation}The numeric values are obtained after solving the equations for $z_o$ and $A_v$ for the target values given below.
Output impedance $z_o$:
\begin{equation} z_{o}=50 \end{equation}Source-to-load voltage transfer $A_v$:
\begin{equation} A_{v}=1 \end{equation}Antenna capacitance $C_A$:
\begin{equation} C_{A}=6.3 \cdot 10^{-12} \end{equation}The T1 matrix of the amplifier should be:
\begin{equation} T_{1}=\left[\begin{matrix}0.5 & 25.0\\0 & 0\end{matrix}\right] \end{equation}Go to ABconcept_index
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Last project update: 2021-03-17 17:27:46