The T1 matrix of the device under test is found as:
\begin{equation} T_{1}=\left[\begin{matrix}0 & 0\\C & D\end{matrix}\right] \end{equation}The matrix equation of the DUT is found as:
\begin{equation} \left[\begin{matrix}V_{i}\\I_{i}\end{matrix}\right]=\left[\begin{matrix}0\\C V_{o} + D I_{o}\end{matrix}\right] \end{equation}The source-to-load transfer is obtained as:
\begin{equation} A_{v}=\frac{C_{A} R_{\ell} s}{C R_{\ell} + D} \end{equation}The input impedance of the DUT is found as:
\begin{equation} z_{i}=0 \end{equation}The output impedance of the DUT is found as:
\begin{equation} z_{o}=\frac{D}{C} \end{equation}The numeric values are obtained after solving the equations for $A_v$ and $z_o$ for the target values given below.
The target value of the source-load voltage transfer $A_v$ is:
\begin{equation} A_{v}=1 \end{equation}The target value of the output impedance $z_o$ is:
\begin{equation} z_{o}=50 \end{equation}The antenna capacitance $C_A$ equals:
\begin{equation} C_{A}=6.3 \cdot 10^{-12} \end{equation}The required parameters of the T1 matrix of the DUT are obtained as:
\begin{equation} T_{1}=\left[\begin{matrix}0 & 0\\3.15 \cdot 10^{-12} s & 1.575 \cdot 10^{-10} s\end{matrix}\right] \end{equation}Go to CDconcept_index
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Last project update: 2022-04-01 07:30:35